There are N buckets numbered from 0 to N−1. There are also M balls of different colors, numbered from 0 to M−1. The K-th ball has color C[K]. For simplicity we denote each color by an integer.
Initially all buckets are empty. At moment K (for K from 0 to M−1), we put the K-th ball into bucket B[K].
Calculate the earliest moment when there are at least Q balls of the same color in some bucket.
Write a function:
class Solution { public int solution(int N, int Q, int[] B, int[] C); }
that, given two integers N and Q, and two arrays B and C consisting of M integers each, returns the earliest moment in which there is some bucket with at least Q balls of the same color. The function should return −1 if no such moment occurs.
Examples:
1. Given N = 3, Q = 2, B = [1, 2, 0, 1, 1, 0, 0, 1] and C = [0, 3, 0, 2, 0, 3, 0, 0], the function should return 4. At moment 3 we have a ball of color 0 in bucket 0, balls of colors 0 and 2 in bucket 1, and a ball of color 3 in bucket 2. At moment 4 we put another ball of color 0 into bucket 1, and there are thus two balls of the same color in this bucket.
2. Given N = 2, Q = 2, B = [0, 1] and C = [5, 5], the function should return −1. There is no moment in which there is some bucket with at least 2 balls of the same color.
3. Given N = 2, Q = 2, B = [0, 1, 0, 1, 0, 1] and C = [1, 3, 0, 0, 3, 3], the function should return 5.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..1,000,000];
- Q and M are integers within the range [1..100,000];
- each element of array B is an integer within the range [0..N-1];
- each element of array C is an integer within the range [0..1,000,000].
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<N; i++) {
buckets[i] = new HashMap<Integer, Integer>();
}
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<N; i++) {
buckets[i] = new HashMap<Integer, Integer>();
}
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<N; i++) {
buckets[i] = new HashMap<Integer, Integer>();
}
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
if(map == null) {
}
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
if(map == null) {
map = new HashMap<Integer, Integer>();
}
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
if(map == null) {
map = new HashMap<Integer, Integer>();
}
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
function result: 0
function result: 2
function result: 2
[500000, 1, [0], [0]]
[2, 2, [1, 1, 1, 1], [0, 1, 0, 1]]
[2, 2, [0, 1, 0, 1], [1, 1, 1, 1]]
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
if(map == null) {
map = new HashMap<Integer, Integer>();
}
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
function result: 0
function result: 2
function result: 2
[500000, 1, [0], [0]]
[2, 2, [1, 1, 1, 1], [0, 1, 0, 1]]
[2, 2, [0, 1, 0, 1], [1, 1, 1, 1]]
// you can also use imports, for example:
import java.util.HashMap;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int N, int Q, int[] B, int[] C) {
// write your code in Java SE 8
Object[] buckets = new Object[N];
for(int i=0; i<B.length; i++) {
int bucketBall = B[i];
int colorBall = C[i];
HashMap<Integer, Integer> map = (HashMap<Integer, Integer>) buckets[bucketBall];
if(map == null) {
map = new HashMap<Integer, Integer>();
}
Integer color = map.get(colorBall);
if (color == null) {
color = new Integer(1);
} else {
color = color.intValue() + 1;
}
if (color.intValue() == Q) {
return i;
} else {
map.put(colorBall, color);
buckets[bucketBall] = map;
}
}
return -1;
}
}
The solution obtained perfect score.