Tasks Details
easy
1.
Brackets
Determine whether a given string of parentheses (multiple types) is properly nested.
Task Score
100%
Correctness
100%
Performance
100%
A string S consisting of N characters is considered to be properly nested if any of the following conditions is true:
- S is empty;
- S has the form "(U)" or "[U]" or "{U}" where U is a properly nested string;
- S has the form "VW" where V and W are properly nested strings.
For example, the string "{[()()]}" is properly nested but "([)()]" is not.
Write a function:
function solution(S);
that, given a string S consisting of N characters, returns 1 if S is properly nested and 0 otherwise.
For example, given S = "{[()()]}", the function should return 1 and given S = "([)()]", the function should return 0, as explained above.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [0..200,000];
- string S is made only of the following characters: '(', '{', '[', ']', '}' and/or ')'.
Copyright 2009–2025 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used JavaScript
Time spent on task 1 minutes
Notes
not defined yet
Task timeline
Code: 19:54:10 UTC,
java,
autosave
Code: 19:54:18 UTC,
js,
verify,
result: Passed
function solution(S) {
// write your code in JavaScript (Node.js 8.9.4)
const oppositeBracket = (bracket) => {
switch (bracket) {
case '}':
return '{';
case ']':
return '[';
case ')':
return '(';
default:
return null;
}
}
const stack = [];
let result = 1;
let c2;
for (let i = 0; i < S.length; i++) {
const c = S[i];
switch (c) {
case '{':
case '[':
case '(':
stack.push(c);
break;
case '}':
case ']':
case ')':
c2 = stack.pop();
if (c2 !== oppositeBracket(c)){
result = 0;
}
break;
default:
break;
}
}
if (stack.length !== 0) {
result = 0;
}
return result;
}
Analysis
Code: 19:54:22 UTC,
js,
final,
score: 
100
function solution(S) {
// write your code in JavaScript (Node.js 8.9.4)
const oppositeBracket = (bracket) => {
switch (bracket) {
case '}':
return '{';
case ']':
return '[';
case ')':
return '(';
default:
return null;
}
}
const stack = [];
let result = 1;
let c2;
for (let i = 0; i < S.length; i++) {
const c = S[i];
switch (c) {
case '{':
case '[':
case '(':
stack.push(c);
break;
case '}':
case ']':
case ')':
c2 = stack.pop();
if (c2 !== oppositeBracket(c)){
result = 0;
}
break;
default:
break;
}
}
if (stack.length !== 0) {
result = 0;
}
return result;
}
Analysis summary
The solution obtained perfect score.
Analysis
Detected time complexity:
O(N)
expand all
Correctness tests
1.
0.068 s
OK
2.
0.068 s
OK
3.
0.068 s
OK
4.
0.068 s
OK
5.
0.068 s
OK
1.
0.068 s
OK
1.
0.068 s
OK
2.
0.068 s
OK
3.
0.068 s
OK
4.
0.068 s
OK
5.
0.068 s
OK
expand all
Performance tests
1.
0.084 s
OK
2.
0.068 s
OK
3.
0.072 s
OK
1.
0.076 s
OK
2.
0.068 s
OK
3.
0.068 s
OK
1.
0.080 s
OK
multiple_full_binary_trees
sequence of full trees of the form T=(TT), depths [1..10..1], with/without some brackets at the end, length=49K+
sequence of full trees of the form T=(TT), depths [1..10..1], with/without some brackets at the end, length=49K+
✔
OK
1.
0.076 s
OK
2.
0.076 s
OK
3.
0.076 s
OK
4.
0.076 s
OK
5.
0.076 s
OK
broad_tree_with_deep_paths
string of the form [TTT...T] of 300 T's, each T being '{{{...}}}' nested 200-fold, length=120K+
string of the form [TTT...T] of 300 T's, each T being '{{{...}}}' nested 200-fold, length=120K+
✔
OK
1.
0.076 s
OK
2.
0.076 s
OK