A non-empty array A consisting of N integers is given.
A permutation is a sequence containing each element from 1 to N once, and only once.
For example, array A such that:
A[0] = 4 A[1] = 1 A[2] = 3 A[3] = 2is a permutation, but array A such that:
A[0] = 4 A[1] = 1 A[2] = 3is not a permutation, because value 2 is missing.
The goal is to check whether array A is a permutation.
Write a function:
class Solution { public int solution(int[] A); }
that, given an array A, returns 1 if array A is a permutation and 0 if it is not.
For example, given array A such that:
A[0] = 4 A[1] = 1 A[2] = 3 A[3] = 2the function should return 1.
Given array A such that:
A[0] = 4 A[1] = 1 A[2] = 3the function should return 0.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..100,000];
- each element of array A is an integer within the range [1..1,000,000,000].
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int n = A.length;
long sum = n * (n+1) / 2;
for(int i=0; i<A.length; i++){
sum -= A[i]
}
}
}
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int n = A.length;
long sum = n * (n+1) / 2;
for(int i=0; i<A.length; i++){
sum -= A[i];
}
if(sum == 0){
return 1;
}else
return 0;
}
}
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int n = A.length;
long sum = n * (n+1) / 2;
for(int i=0; i<A.length; i++){
sum -= A[i];
}
if(sum == 0)
return 1;
else
return 0;
}
}
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int n = A.length;
long sum = n * (n+1) / 2;
for(int i=0; i<A.length; i++){
sum -= A[i];
}
if(sum == 0)
return 1;
else
return 0;
}
}
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int n = A.length;
long sum = n * (n+1) / 2;
for(int i=0; i<A.length; i++){
sum -= A[i];
}
if(sum == 0)
return 1;
else
return 0;
}
}
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int n = A.length;
long sum = n * (n+1) / 2;
for(int i=0; i<A.length; i++){
sum -= A[i];
}
if(sum == 0)
return 1;
else
return 0;
}
}
The following issues have been detected: wrong answers.
For example, for the input [1, 4, 1] the solution returned a wrong answer (got 1 expected 0).
total sum is correct, but it is not a permutation, N <= 10
got 1 expected 0
permutations of sets like [2..100] for which the anwsers should be false