Tasks Details
easy
1.
PermCheck
Check whether array A is a permutation.
Task Score
100%
Correctness
100%
Performance
100%
A non-empty array A consisting of N integers is given.
A permutation is a sequence containing each element from 1 to N once, and only once.
For example, array A such that:
A[0] = 4 A[1] = 1 A[2] = 3 A[3] = 2is a permutation, but array A such that:
A[0] = 4 A[1] = 1 A[2] = 3is not a permutation, because value 2 is missing.
The goal is to check whether array A is a permutation.
Write a function:
int solution(vector<int> &A);
that, given an array A, returns 1 if array A is a permutation and 0 if it is not.
For example, given array A such that:
A[0] = 4 A[1] = 1 A[2] = 3 A[3] = 2the function should return 1.
Given array A such that:
A[0] = 4 A[1] = 1 A[2] = 3the function should return 0.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..100,000];
- each element of array A is an integer within the range [1..1,000,000,000].
Copyright 2009–2024 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used C++
Time spent on task 1 minutes
Notes
not defined yet
Task timeline
Code: 10:16:17 UTC,
java,
autosave
Code: 10:16:28 UTC,
cpp,
autosave
// you can use includes, for example:
// #include <algorithm>
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
#define SIZEA 1000000000
int solution(vector<int> &A) {
auto pbits = new bitset<SIZEA>;
pbits->reset();
for (size_t i = 0; i < A.size(); i++) {
int el = A[i];
if ((*pbits)[el]) {
return 0;
}
(*pbits)[el] = true;
}
for (uint i = 0; i < A.size(); i++) {
if (!(*pbits)[i+1]) {
return 0;
}
}
return 1;
}
Code: 10:16:37 UTC,
cpp,
verify,
result: Passed
// you can use includes, for example:
// #include <algorithm>
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
#include <bitset>
#define SIZEA 1000000000
int solution(vector<int> &A) {
auto pbits = new bitset<SIZEA>;
pbits->reset();
for (size_t i = 0; i < A.size(); i++) {
int el = A[i];
if ((*pbits)[el]) {
return 0;
}
(*pbits)[el] = true;
}
for (uint i = 0; i < A.size(); i++) {
if (!(*pbits)[i+1]) {
return 0;
}
}
return 1;
}
Analysis
Code: 10:16:46 UTC,
cpp,
verify,
result: Passed
// you can use includes, for example:
// #include <algorithm>
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
#include <bitset>
#define SIZEA 1000000000
int solution(vector<int> &A) {
auto pbits = new bitset<SIZEA>;
pbits->reset();
for (size_t i = 0; i < A.size(); i++) {
int el = A[i];
if ((*pbits)[el]) {
return 0;
}
(*pbits)[el] = true;
}
for (uint i = 0; i < A.size(); i++) {
if (!(*pbits)[i+1]) {
return 0;
}
}
return 1;
}
Analysis
Code: 10:16:50 UTC,
cpp,
final,
score: 
100
// you can use includes, for example:
// #include <algorithm>
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
#include <bitset>
#define SIZEA 1000000000
int solution(vector<int> &A) {
auto pbits = new bitset<SIZEA>;
pbits->reset();
for (size_t i = 0; i < A.size(); i++) {
int el = A[i];
if ((*pbits)[el]) {
return 0;
}
(*pbits)[el] = true;
}
for (uint i = 0; i < A.size(); i++) {
if (!(*pbits)[i+1]) {
return 0;
}
}
return 1;
}
Analysis summary
The solution obtained perfect score.
Analysis
Detected time complexity:
O(N) or O(N * log(N))
expand all
Correctness tests
1.
0.080 s
OK
2.
0.080 s
OK
1.
0.080 s
OK
2.
0.080 s
OK
1.
0.080 s
OK
2.
0.080 s
OK
3.
0.080 s
OK
4.
0.080 s
OK
1.
0.080 s
OK
2.
0.080 s
OK
3.
0.080 s
OK
4.
0.080 s
OK
1.
0.080 s
OK
2.
0.080 s
OK
permutations_of_ranges
permutations of sets like [2..100] for which the anwsers should be false
permutations of sets like [2..100] for which the anwsers should be false
✔
OK
1.
0.080 s
OK
2.
0.080 s
OK
3.
0.080 s
OK
expand all
Performance tests
1.
0.080 s
OK
2.
0.080 s
OK
1.
0.084 s
OK
2.
0.084 s
OK
1.
0.084 s
OK
2.
0.084 s
OK
1.
0.084 s
OK
2.
0.084 s
OK
1.
0.080 s
OK
2.
0.080 s
OK
3.
0.080 s
OK
1.
0.080 s
OK
2.
0.080 s
OK
3.
0.080 s
OK
4.
0.088 s
OK
5.
0.084 s
OK