Tasks Details
medium
1.
CountDiv
Compute number of integers divisible by k in range [a..b].
Task Score
100%
Correctness
100%
Performance
100%
Write a function:
function solution(A, B, K);
that, given three integers A, B and K, returns the number of integers within the range [A..B] that are divisible by K, i.e.:
{ i : A ≤ i ≤ B, i mod K = 0 }
For example, for A = 6, B = 11 and K = 2, your function should return 3, because there are three numbers divisible by 2 within the range [6..11], namely 6, 8 and 10.
Write an efficient algorithm for the following assumptions:
- A and B are integers within the range [0..2,000,000,000];
- K is an integer within the range [1..2,000,000,000];
- A ≤ B.
Copyright 2009–2025 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used JavaScript
Time spent on task 15 minutes
Notes
not defined yet
Code: 07:58:17 UTC,
java,
autosave
Code: 08:05:53 UTC,
js,
autosave
Code: 08:05:54 UTC,
js,
verify,
result: Passed
Analysis
Code: 08:08:40 UTC,
js,
autosave
Code: 08:08:56 UTC,
js,
autosave
Code: 08:09:07 UTC,
js,
autosave
Code: 08:09:18 UTC,
js,
autosave
Code: 08:09:31 UTC,
js,
autosave
Code: 08:09:42 UTC,
js,
autosave
Code: 08:09:53 UTC,
js,
autosave
Code: 08:10:06 UTC,
js,
autosave
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A, B, K) {
// Implement your solution here
var counter = 0;
for(var i = A;i<=B;i++){
if(i%K == 0) counter++
}
var minimum_divisible = K*Math.ceil(A/K)
var maximum
return counter
}
Code: 08:10:11 UTC,
js,
autosave
Code: 08:10:20 UTC,
js,
autosave
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A, B, K) {
// Implement your solution here
var counter = 0;
for(var i = A;i<=B;i++){
if(i%K == 0) counter++
}
var minimum_divisible = K*Math.ceil(A/K)
var maximum_divisible = K*Math.floor(B/K)
return counter
}
Code: 08:11:36 UTC,
js,
autosave
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A, B, K) {
// Implement your solution here
var counter = 0;
for(var i = A;i<=B;i++){
if(i%K == 0) counter++
}
var minimum_divisible = K*Math.ceil(A/K)
var maximum_divisible = K*Math.floor(B/K)
return counter
}
Code: 08:11:47 UTC,
js,
autosave
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A, B, K) {
// Implement your solution here
var counter = 0;
for(var i = A;i<=B;i++){
if(i%K == 0) counter++
}
var minimum_divisible = K*Math.ceil(A/K)
var maximum_divisible = K*Math.floor(B/K)
(maximum_divisible - minimum_divisible)
return counter
}
Code: 08:12:00 UTC,
js,
autosave
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A, B, K) {
// Implement your solution here
var counter = 0;
for(var i = A;i<=B;i++){
if(i%K == 0) counter++
}
var minimum_divisible = K*Math.ceil(A/K)
var maximum_divisible = K*Math.floor(B/K)
(maximum_divisible - minimum_divisible)/K
return counter
}
Code: 08:12:22 UTC,
js,
verify,
result: Passed
Analysis
Code: 08:12:27 UTC,
js,
verify,
result: Passed
Analysis
Code: 08:12:32 UTC,
js,
final,
score: 
100
Analysis summary
The solution obtained perfect score.
Analysis
Detected time complexity:
O(1)
expand all
Correctness tests
1.
0.052 s
OK
1.
0.056 s
OK
2.
0.052 s
OK
1.
0.052 s
OK
2.
0.052 s
OK
3.
0.052 s
OK
1.
0.052 s
OK
2.
0.052 s
OK
3.
0.052 s
OK
4.
0.052 s
OK
5.
0.056 s
OK
6.
0.052 s
OK
expand all
Performance tests
1.
0.052 s
OK
1.
0.052 s
OK
1.
0.052 s
OK
2.
0.052 s
OK
1.
0.052 s
OK
2.
0.052 s
OK
3.
0.052 s
OK
4.
0.052 s
OK