Tasks Details
easy
1.
Triangle
Determine whether a triangle can be built from a given set of edges.
Task Score
93%
Correctness
100%
Performance
83%
An array A consisting of N integers is given. A triplet (P, Q, R) is triangular if 0 ≤ P < Q < R < N and:
- A[P] + A[Q] > A[R],
- A[Q] + A[R] > A[P],
- A[R] + A[P] > A[Q].
For example, consider array A such that:
A[0] = 10 A[1] = 2 A[2] = 5 A[3] = 1 A[4] = 8 A[5] = 20Triplet (0, 2, 4) is triangular.
Write a function:
class Solution { public int solution(int[] A); }
that, given an array A consisting of N integers, returns 1 if there exists a triangular triplet for this array and returns 0 otherwise.
For example, given array A such that:
A[0] = 10 A[1] = 2 A[2] = 5 A[3] = 1 A[4] = 8 A[5] = 20the function should return 1, as explained above. Given array A such that:
A[0] = 10 A[1] = 50 A[2] = 5 A[3] = 1the function should return 0.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [−2,147,483,648..2,147,483,647].
Copyright 2009–2025 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used Java 8
Time spent on task 1 minutes
Notes
not defined yet
Code: 19:31:19 UTC,
java,
autosave
Code: 19:31:29 UTC,
java,
autosave
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int[] array = filterLessThanOneElements(unfilteredArray);
for(int i = 0; i <= (array.length - 3) ; i++) {
long p = array[i];
for(int j = i+1; j <= (array.length - 2); j++) {
long q = array[j];
for(int k = j+1; k <= (array.length - 1); k++) {
long r = array[k];
if((p + q > r) && (q + r > p) && (r + p > q)) {
return 1;
}
}
}
}
return 0;
}
}
Code: 19:31:42 UTC,
java,
verify,
result: Failed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] unfilteredArray) {
int[] array = filterLessThanOneElements(unfilteredArray);
for(int i = 0; i <= (array.length - 3) ; i++) {
long p = array[i];
for(int j = i+1; j <= (array.length - 2); j++) {
long q = array[j];
for(int k = j+1; k <= (array.length - 1); k++) {
long r = array[k];
if((p + q > r) && (q + r > p) && (r + p > q)) {
return 1;
}
}
}
}
return 0;
}
// The mose efficient way to remove duplicates
// TIME COMPLEXITY : O(N)
private static int[] filterLessThanOneElements(int[] unfilteredArray) {
int k = 0;
for(int i = 0; i < unfilteredArray.length; i++) {
if(unfilteredArray[i] > 0) {
unfilteredArray[k++] = unfilteredArray[i];
}
}
return Arrays.copyOfRange(unfilteredArray, 0, k);
}
}
Analysis
Compile error
Solution.java:37: error: cannot find symbol return Arrays.copyOfRange(unfilteredArray, 0, k); ^ symbol: variable Arrays location: class Solution 1 error
Code: 19:31:53 UTC,
java,
verify,
result: Passed
// you can also use imports, for example:
// import java.util.*;
import java.util.Arrays;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] unfilteredArray) {
int[] array = filterLessThanOneElements(unfilteredArray);
for(int i = 0; i <= (array.length - 3) ; i++) {
long p = array[i];
for(int j = i+1; j <= (array.length - 2); j++) {
long q = array[j];
for(int k = j+1; k <= (array.length - 1); k++) {
long r = array[k];
if((p + q > r) && (q + r > p) && (r + p > q)) {
return 1;
}
}
}
}
return 0;
}
// The mose efficient way to remove duplicates
// TIME COMPLEXITY : O(N)
private static int[] filterLessThanOneElements(int[] unfilteredArray) {
int k = 0;
for(int i = 0; i < unfilteredArray.length; i++) {
if(unfilteredArray[i] > 0) {
unfilteredArray[k++] = unfilteredArray[i];
}
}
return Arrays.copyOfRange(unfilteredArray, 0, k);
}
}
Analysis
Code: 19:32:00 UTC,
java,
verify,
result: Passed
// you can also use imports, for example:
// import java.util.*;
import java.util.Arrays;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] unfilteredArray) {
int[] array = filterLessThanOneElements(unfilteredArray);
for(int i = 0; i <= (array.length - 3) ; i++) {
long p = array[i];
for(int j = i+1; j <= (array.length - 2); j++) {
long q = array[j];
for(int k = j+1; k <= (array.length - 1); k++) {
long r = array[k];
if((p + q > r) && (q + r > p) && (r + p > q)) {
return 1;
}
}
}
}
return 0;
}
// The mose efficient way to remove duplicates
// TIME COMPLEXITY : O(N)
private static int[] filterLessThanOneElements(int[] unfilteredArray) {
int k = 0;
for(int i = 0; i < unfilteredArray.length; i++) {
if(unfilteredArray[i] > 0) {
unfilteredArray[k++] = unfilteredArray[i];
}
}
return Arrays.copyOfRange(unfilteredArray, 0, k);
}
}
Analysis
Code: 19:32:04 UTC,
java,
final,
score: 
93
// you can also use imports, for example:
// import java.util.*;
import java.util.Arrays;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] unfilteredArray) {
int[] array = filterLessThanOneElements(unfilteredArray);
for(int i = 0; i <= (array.length - 3) ; i++) {
long p = array[i];
for(int j = i+1; j <= (array.length - 2); j++) {
long q = array[j];
for(int k = j+1; k <= (array.length - 1); k++) {
long r = array[k];
if((p + q > r) && (q + r > p) && (r + p > q)) {
return 1;
}
}
}
}
return 0;
}
// The mose efficient way to remove duplicates
// TIME COMPLEXITY : O(N)
private static int[] filterLessThanOneElements(int[] unfilteredArray) {
int k = 0;
for(int i = 0; i < unfilteredArray.length; i++) {
if(unfilteredArray[i] > 0) {
unfilteredArray[k++] = unfilteredArray[i];
}
}
return Arrays.copyOfRange(unfilteredArray, 0, k);
}
}
Analysis summary
The following issues have been detected: timeout errors.
Analysis
Detected time complexity:
O(N*log(N))
expand all
Correctness tests
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.004 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.004 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.012 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.008 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.004 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
expand all
Performance tests
1.
0.032 s
OK
2.
0.012 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
large2
1 followed by an ascending sequence of ~50K elements from [0..100K], length=~50K
1 followed by an ascending sequence of ~50K elements from [0..100K], length=~50K
✘
TIMEOUT ERROR
Killed. Hard limit reached: 6.000 sec.
Killed. Hard limit reached: 6.000 sec.
1.
6.000 s
TIMEOUT ERROR,
Killed. Hard limit reached: 6.000 sec.
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.248 s
OK
2.
0.004 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.252 s
OK
2.
0.004 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.168 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK
1.
0.164 s
OK
2.
0.008 s
OK
3.
0.008 s
OK
4.
0.008 s
OK
5.
0.008 s
OK
6.
0.008 s
OK