Tasks Details
easy
Maximize A[P] * A[Q] * A[R] for any triplet (P, Q, R).
Task Score
100%
Correctness
100%
Performance
100%
A non-empty array A consisting of N integers is given. The product of triplet (P, Q, R) equates to A[P] * A[Q] * A[R] (0 ≤ P < Q < R < N).
For example, array A such that:
A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6contains the following example triplets:
- (0, 1, 2), product is −3 * 1 * 2 = −6
- (1, 2, 4), product is 1 * 2 * 5 = 10
- (2, 4, 5), product is 2 * 5 * 6 = 60
Your goal is to find the maximal product of any triplet.
Write a function:
int solution(vector<int> &A);
that, given a non-empty array A, returns the value of the maximal product of any triplet.
For example, given array A such that:
A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6the function should return 60, as the product of triplet (2, 4, 5) is maximal.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [3..100,000];
- each element of array A is an integer within the range [−1,000..1,000].
Copyright 2009–2024 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used C++
Time spent on task 1 minutes
Notes
not defined yet
Task timeline
Code: 16:49:33 UTC,
java,
autosave
Code: 16:49:34 UTC,
cpp,
autosave
Code: 16:49:39 UTC,
cpp,
autosave
// you can use includes, for example:
#include <algorithm>
using namespace std;
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
int solution(vector<int> &A) {
// write your code in C++14 (g++ 6.2.0)
int index = A.size() - 1;
int P_max, M_max;
sort(A.begin(), A.end());
P_max = A.at(index) * A.at(index - 1);
M_max = A.at(0) * A.at(1);
if(M_max > P_max){
if(A.at(index) < 0)
return P_max * A.at(index - 2);
else
return M_max * A.at(index);
}else
return P_max * A.at(index - 2);
}
Code: 16:49:52 UTC,
cpp,
autosave
// you can use includes, for example:
#include <algorithm>
using namespace std;
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
int solution(vector<int> &A) {
// write your code in C++14 (g++ 6.2.0)
int index = A.size() - 1;
int P_max, M_max;
sort(A.begin(), A.end());
P_max = A.at(index - 1) * A.at(index - 2);
M_max = A.at(0) * A.at(1);
if(M_max > P_max){
if(A.at(index) < 0)
return P_max * A.at(index - 2);
else
return M_max * A.at(index);
}else
return P_max * A.at(index - 2);
}
Code: 16:50:03 UTC,
cpp,
autosave
// you can use includes, for example:
#include <algorithm>
using namespace std;
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
int solution(vector<int> &A) {
// write your code in C++14 (g++ 6.2.0)
int index = A.size() - 1;
int P_max, M_max;
sort(A.begin(), A.end());
P_max = A.at(index - 1) * A.at(index - 2);
M_max = A.at(0) * A.at(1);
if(M_max > P_max){
if(A.at(index) < 0)
return P_max * A.at(index);
else
return M_max * A.at(index);
}else
return P_max * A.at(index - 2);
}
Code: 16:50:04 UTC,
cpp,
verify,
result: Passed
// you can use includes, for example:
#include <algorithm>
using namespace std;
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
int solution(vector<int> &A) {
// write your code in C++14 (g++ 6.2.0)
int index = A.size() - 1;
int P_max, M_max;
sort(A.begin(), A.end());
P_max = A.at(index - 1) * A.at(index - 2);
M_max = A.at(0) * A.at(1);
if(M_max > P_max){
if(A.at(index) < 0)
return P_max * A.at(index);
else
return M_max * A.at(index);
}else
return P_max * A.at(index);
}
Analysis
Code: 16:50:08 UTC,
cpp,
verify,
result: Passed
// you can use includes, for example:
#include <algorithm>
using namespace std;
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
int solution(vector<int> &A) {
// write your code in C++14 (g++ 6.2.0)
int index = A.size() - 1;
int P_max, M_max;
sort(A.begin(), A.end());
P_max = A.at(index - 1) * A.at(index - 2);
M_max = A.at(0) * A.at(1);
if(M_max > P_max){
if(A.at(index) < 0)
return P_max * A.at(index);
else
return M_max * A.at(index);
}else
return P_max * A.at(index);
}
Analysis
Code: 16:50:11 UTC,
cpp,
final,
score: 
100
// you can use includes, for example:
#include <algorithm>
using namespace std;
// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;
int solution(vector<int> &A) {
// write your code in C++14 (g++ 6.2.0)
int index = A.size() - 1;
int P_max, M_max;
sort(A.begin(), A.end());
P_max = A.at(index - 1) * A.at(index - 2);
M_max = A.at(0) * A.at(1);
if(M_max > P_max){
if(A.at(index) < 0)
return P_max * A.at(index);
else
return M_max * A.at(index);
}else
return P_max * A.at(index);
}
Analysis summary
The solution obtained perfect score.
Analysis
Detected time complexity:
O(N * log(N))
expand all
Correctness tests
1.
0.001 s
OK
2.
0.001 s
OK
3.
0.001 s
OK
1.
0.001 s
OK
2.
0.001 s
OK
3.
0.001 s
OK
4.
0.001 s
OK
1.
0.001 s
OK
2.
0.001 s
OK
3.
0.001 s
OK
1.
0.001 s
OK
expand all
Performance tests
1.
0.001 s
OK
1.
0.001 s
OK
1.
0.012 s
OK
1.
0.004 s
OK
1.
0.004 s
OK
2.
0.008 s
OK