A DNA sequence can be represented as a string consisting of the letters A, C, G and T, which correspond to the types of successive nucleotides in the sequence. Each nucleotide has an impact factor, which is an integer. Nucleotides of types A, C, G and T have impact factors of 1, 2, 3 and 4, respectively. You are going to answer several queries of the form: What is the minimal impact factor of nucleotides contained in a particular part of the given DNA sequence?
The DNA sequence is given as a non-empty string S = S[0]S[1]...S[N-1] consisting of N characters. There are M queries, which are given in non-empty arrays P and Q, each consisting of M integers. The K-th query (0 ≤ K < M) requires you to find the minimal impact factor of nucleotides contained in the DNA sequence between positions P[K] and Q[K] (inclusive).
For example, consider string S = CAGCCTA and arrays P, Q such that:
P[0] = 2 Q[0] = 4 P[1] = 5 Q[1] = 5 P[2] = 0 Q[2] = 6The answers to these M = 3 queries are as follows:
- The part of the DNA between positions 2 and 4 contains nucleotides G and C (twice), whose impact factors are 3 and 2 respectively, so the answer is 2.
 - The part between positions 5 and 5 contains a single nucleotide T, whose impact factor is 4, so the answer is 4.
 - The part between positions 0 and 6 (the whole string) contains all nucleotides, in particular nucleotide A whose impact factor is 1, so the answer is 1.
 
Write a function:
class Solution { public int[] solution(String S, int[] P, int[] Q); }
that, given a non-empty string S consisting of N characters and two non-empty arrays P and Q consisting of M integers, returns an array consisting of M integers specifying the consecutive answers to all queries.
Result array should be returned as an array of integers.
For example, given the string S = CAGCCTA and arrays P, Q such that:
P[0] = 2 Q[0] = 4 P[1] = 5 Q[1] = 5 P[2] = 0 Q[2] = 6the function should return the values [2, 4, 1], as explained above.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..100,000];
 - M is an integer within the range [1..50,000];
 - each element of arrays P and Q is an integer within the range [0..N - 1];
 - P[K] ≤ Q[K], where 0 ≤ K < M;
 - string S consists only of upper-case English letters A, C, G, T.
 
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0.
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = A[idx];
            A[idx + 1] = A[idx];
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': break;
                case 'C': break;
                case 'G': break;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': break;
                default: break;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++)
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++) {
            if ()
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P])
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if () {
                
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        // Check for contains word in P and Q.
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        // Check for contains word in P and Q.
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            Solution.java:11: error: cannot find symbol
        int[] A = new int[S.length + 1];
                           ^
  symbol:   variable length
  location: variable S of type String
Solution.java:12: error: cannot find symbol
        int[] C = new int[S.length + 1];
                           ^
  symbol:   variable length
  location: variable S of type String
Solution.java:13: error: cannot find symbol
        int[] G = new int[S.length + 1];
                           ^
  symbol:   variable length
  location: variable S of type String
3 errors
  
          
            
          
        
      // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length() + 1];
        int[] C = new int[S.length + 1];
        int[] G = new int[S.length + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        // Check for contains word in P and Q.
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length() + 1];
        int[] C = new int[S.length() + 1];
        int[] G = new int[S.length() + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        // Check for contains word in P and Q.
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length() + 1];
        int[] C = new int[S.length() + 1];
        int[] G = new int[S.length() + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        // Check for contains word in P and Q.
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            // you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
    public int[] solution(String S, int[] P, int[] Q) {
        int[] result = new int[P.length];
        // All array is start 0. (Check for changing character is exists.)
        int[] A = new int[S.length() + 1];
        int[] C = new int[S.length() + 1];
        int[] G = new int[S.length() + 1];
        // Initializing each array.
        for (int idx = 0; idx < S.length(); idx++) {
            A[idx + 1] = A[idx];
            C[idx + 1] = C[idx];
            G[idx + 1] = G[idx];
            switch(S.charAt(idx)) {
                case 'A': A[idx + 1]++; break;
                case 'C': C[idx + 1]++; break;
                case 'G': G[idx + 1]++; break;
                default: break;
            }
        }
        // Check for contains word in P and Q.
        for (int idx = 0; idx < P.length; idx++) {
            if (A[P[idx]] != A[Q[idx] + 1]) {
                result[idx] = 1;
            } else if (C[P[idx]] != C[Q[idx] + 1]) {
                result[idx] = 2;
            } else if (G[P[idx]] != G[Q[idx] + 1]) {
                result[idx] = 3;
            } else {
                result[idx] = 4;
            }
        }
        return result;
    }
}
            The solution obtained perfect score.