Tasks Details
easy
1.
PassingCars
Count the number of passing cars on the road.
Task Score
100%
Correctness
100%
Performance
100%
A non-empty array A consisting of N integers is given. The consecutive elements of array A represent consecutive cars on a road.
Array A contains only 0s and/or 1s:
- 0 represents a car traveling east,
- 1 represents a car traveling west.
The goal is to count passing cars. We say that a pair of cars (P, Q), where 0 ≤ P < Q < N, is passing when P is traveling to the east and Q is traveling to the west.
For example, consider array A such that:
A[0] = 0 A[1] = 1 A[2] = 0 A[3] = 1 A[4] = 1We have five pairs of passing cars: (0, 1), (0, 3), (0, 4), (2, 3), (2, 4).
Write a function:
class Solution { public int solution(int[] A); }
that, given a non-empty array A of N integers, returns the number of pairs of passing cars.
The function should return −1 if the number of pairs of passing cars exceeds 1,000,000,000.
For example, given:
A[0] = 0 A[1] = 1 A[2] = 0 A[3] = 1 A[4] = 1the function should return 5, as explained above.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..100,000];
- each element of array A is an integer that can have one of the following values: 0, 1.
Copyright 2009–2024 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used Java 8
Time spent on task 4 minutes
Notes
not defined yet
Task timeline
Code: 02:54:45 UTC,
java,
autosave
Code: 02:56:30 UTC,
java,
autosave
Code: 02:57:00 UTC,
java,
autosave
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
}
return result;
}
}
Code: 02:57:20 UTC,
java,
autosave
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
if (result > 1000000000) {
return -1;
}
}
return result;
}
}
Code: 02:57:21 UTC,
java,
verify,
result: Passed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
if (result > 1000000000) {
return -1;
}
}
return result;
}
}
Analysis
Code: 02:57:39 UTC,
java,
autosave
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
// If passing cars
if (result > 1000000000) {
return -1;
}
}
return result;
}
}
Code: 02:58:00 UTC,
java,
autosave
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
// If passing cars exeeds 1,000,000,000, return -1.
if (result > 1000000000) {
return -1;
}
}
return result;
}
}
Code: 02:58:04 UTC,
java,
verify,
result: Passed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
// If passing cars exeeds 1,000,000,000, return -1.
if (result > 1000000000) {
return -1;
}
}
return result;
}
}
Analysis
Code: 02:58:09 UTC,
java,
final,
score:
100
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
class Solution {
public int solution(int[] A) {
int count = 0;
int result = 0;
for (int num : A) {
if (num == 0) {
count++;
} else {
result += count;
}
// If passing cars exeeds 1,000,000,000, return -1.
if (result > 1000000000) {
return -1;
}
}
return result;
}
}
Analysis summary
The solution obtained perfect score.
Analysis
Detected time complexity:
O(N)
expand all
Correctness tests
1.
0.008 s
OK
2.
0.012 s
OK
1.
0.004 s
OK
2.
0.004 s
OK
3.
0.004 s
OK
4.
0.004 s
OK
1.
0.004 s
OK
1.
0.004 s
OK
1.
0.008 s
OK
expand all
Performance tests
1.
0.020 s
OK
1.
0.156 s
OK
1.
0.160 s
OK
2.
0.116 s
OK
1.
0.164 s
OK
2.
0.144 s
OK
1.
0.200 s
OK
2.
0.152 s
OK
3.
0.152 s
OK