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            1.
            
              FrogJmp
            
          
          
            Count minimal number of jumps from position X to Y.
          
        
  
    
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        A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D.
Count the minimal number of jumps that the small frog must perform to reach its target.
Write a function:
class Solution { public int solution(int X, int Y, int D); }
that, given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y.
For example, given:
X = 10 Y = 85 D = 30the function should return 3, because the frog will be positioned as follows:
- after the first jump, at position 10 + 30 = 40
 - after the second jump, at position 10 + 30 + 30 = 70
 - after the third jump, at position 10 + 30 + 30 + 30 = 100
 
Write an efficient algorithm for the following assumptions:
- X, Y and D are integers within the range [1..1,000,000,000];
 - X ≤ Y.
 
Copyright 2009–2025 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
              
            
          
            Solution
            
            
              
                
              
            
          
          
          
            
              Programming language used Java 21
            
          
          
            
            
              Time spent on task 5 minutes
              
            
            
          
          
          
            
              
                
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