Your browser (Unknown 0) is no longer supported. Some parts of the website may not work correctly. Please update your browser.

AVAILABLE LESSONS:

Lesson 1

Iterations

Lesson 2

Arrays

Lesson 3

Time Complexity

Lesson 4

Counting Elements

Lesson 5

Prefix Sums

Lesson 6

Sorting

Lesson 7

Stacks and Queues

Lesson 8

Leader

Lesson 9

Maximum slice problem

Lesson 10

Prime and composite numbers

Lesson 11

Sieve of Eratosthenes

Lesson 12

Euclidean algorithm

Lesson 13

Fibonacci numbers

Lesson 14

Binary search algorithm

Lesson 15

Caterpillar method

Lesson 16

Greedy algorithms

Lesson 17

Dynamic programming

Lesson 90

Tasks from Indeed Prime 2015 challenge

Lesson 91

Tasks from Indeed Prime 2016 challenge

Lesson 92

Tasks from Indeed Prime 2016 College Coders challenge

Lesson 99

Future training

respectable

Calculate the values of counters after applying all alternating operations: increase counter by 1; set value of all counters to current maximum.

Programming language:
Spoken language:

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Assume that the following declarations are given:

struct Results { int * C; int L; // Length of the array };

Write a function:

struct Results solution(int N, int A[], int M);

that, given an integer N and a non-empty array A consisting of M integers, returns a sequence of integers representing the values of the counters.

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);
- expected worst-case space complexity is O(N) (not counting the storage required for input arguments).

Copyright 2009–2018 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

vector<int> solution(int N, vector<int> &A);

that, given an integer N and a non-empty array A consisting of M integers, returns a sequence of integers representing the values of the counters.

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);
- expected worst-case space complexity is O(N) (not counting the storage required for input arguments).

Copyright 2009–2018 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

class Solution { public int[] solution(int N, int[] A); }

that, given an integer N and a non-empty array A consisting of M integers, returns a sequence of integers representing the values of the counters.

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);
- expected worst-case space complexity is O(N) (not counting the storage required for input arguments).

Copyright 2009–2018 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

func Solution(N int, A []int) []int

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

class Solution { public int[] solution(int N, int[] A); }

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

function solution(N, A);

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

function solution(N, A)

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

Note: All arrays in this task are zero-indexed, unlike the common Lua convention. You can use `#A` to get the length of the array A.

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

NSMutableArray * solution(int N, NSMutableArray *A);

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Assume that the following declarations are given:

Results = record C : array of longint; L : longint; {Length of the array} end;

Write a function:

function solution(N: longint; A: array of longint; M: longint): Results;

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

function solution($N, $A);

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

sub solution { my ($N, @A)=@_; ... }

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

def solution(N, A)

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

def solution(n, a)

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

object Solution { def solution(n: Int, a: Array[Int]): Array[Int] }

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

public func solution(N : Int, inout _ A : [Int]) -> [Int]

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

public func solution(_ N : Int, _ A : inout [Int]) -> [Int]

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

You are given N counters, initially set to 0, and you have two possible operations on them:

increase(X)− counter X is increased by 1,max counter− all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

- if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
- if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

the values of the counters after each consecutive operation will be:

The goal is to calculate the value of every counter after all operations.

Write a function:

Private Function solution(N As Integer, A As Integer()) As Integer()

The sequence should be returned as:

- a structure Results (in C), or
- a vector of integers (in C++), or
- a record Results (in Pascal), or
- an array of integers (in any other programming language).

For example, given:

the function should return [3, 2, 2, 4, 2], as explained above.

Assume that:

- N and M are integers within the range [1..100,000];
- each element of array A is an integer within the range [1..N + 1].

Complexity:

- expected worst-case time complexity is O(N+M);

Information about upcoming challenges, solutions and lessons directly in your inbox.

© 2009–2018 Codility Ltd., registered in England and Wales (No. 7048726). VAT ID GB981191408. Registered office: 107 Cheapside, London EC2V 6DN