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ambitious

Given an array A, count the number of different triplets (a, b, c) in which a occurs before b and b occurs before c.

Programming language:
Spoken language:

Kate was given a birthday gift of three theater tickets. Now she is browsing the theater program for the next N days. On the program, performances are named by integers. Every day, one performance is staged. Kate wants to choose three days (not necessarily consecutive) to go to the theater.

In how many ways can she use her tickets? Two ways are different if the sequences of watched performances are different. Kate likes the theater, so she may watch one performance more than once. For example, if N = 4 and theater program looks as following: [1, 2, 1, 1], Kate has four possibilities to choose the dates: [**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

int solution(int A[], int N);

that, given an array A consisting of N integers, denoting names of performances for the next N days, returns the number of possible ways to spend the tickets. Since the answer can be very large, provide it modulo 10^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2, 3, 4], the function should return 4. There are four ways to spend tickets: (1, 2, 3), (1, 2, 4), (1, 3, 4) and (2, 3, 4).

Given A = [2, 2, 2, 2], the function should return 1. There is only one way to spend tickets: (2, 2, 2).

Given A = [2, 2, 1, 2, 2], the function should return 4. There are four ways to spend tickets: (1, 2, 2), (2, 1, 2), (2, 2, 1) and (2, 2, 2).

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);
- expected worst-case space complexity is O(N) (not counting the storage required for input arguments).

Copyright 2009–2018 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

Kate was given a birthday gift of three theater tickets. Now she is browsing the theater program for the next N days. On the program, performances are named by integers. Every day, one performance is staged. Kate wants to choose three days (not necessarily consecutive) to go to the theater.

In how many ways can she use her tickets? Two ways are different if the sequences of watched performances are different. Kate likes the theater, so she may watch one performance more than once. For example, if N = 4 and theater program looks as following: [1, 2, 1, 1], Kate has four possibilities to choose the dates: [**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

int solution(vector<int> &A);

that, given an array A consisting of N integers, denoting names of performances for the next N days, returns the number of possible ways to spend the tickets. Since the answer can be very large, provide it modulo 10^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2, 3, 4], the function should return 4. There are four ways to spend tickets: (1, 2, 3), (1, 2, 4), (1, 3, 4) and (2, 3, 4).

Given A = [2, 2, 2, 2], the function should return 1. There is only one way to spend tickets: (2, 2, 2).

Given A = [2, 2, 1, 2, 2], the function should return 4. There are four ways to spend tickets: (1, 2, 2), (2, 1, 2), (2, 2, 1) and (2, 2, 2).

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);
- expected worst-case space complexity is O(N) (not counting the storage required for input arguments).

Copyright 2009–2018 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

Kate was given a birthday gift of three theater tickets. Now she is browsing the theater program for the next N days. On the program, performances are named by integers. Every day, one performance is staged. Kate wants to choose three days (not necessarily consecutive) to go to the theater.

In how many ways can she use her tickets? Two ways are different if the sequences of watched performances are different. Kate likes the theater, so she may watch one performance more than once. For example, if N = 4 and theater program looks as following: [1, 2, 1, 1], Kate has four possibilities to choose the dates: [**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

class Solution { public int solution(int[] A); }

that, given an array A consisting of N integers, denoting names of performances for the next N days, returns the number of possible ways to spend the tickets. Since the answer can be very large, provide it modulo 10^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2, 3, 4], the function should return 4. There are four ways to spend tickets: (1, 2, 3), (1, 2, 4), (1, 3, 4) and (2, 3, 4).

Given A = [2, 2, 2, 2], the function should return 1. There is only one way to spend tickets: (2, 2, 2).

Given A = [2, 2, 1, 2, 2], the function should return 4. There are four ways to spend tickets: (1, 2, 2), (2, 1, 2), (2, 2, 1) and (2, 2, 2).

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);
- expected worst-case space complexity is O(N) (not counting the storage required for input arguments).

Copyright 2009–2018 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

func Solution(A []int) int

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

class Solution { public int solution(int[] A); }

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

function solution(A);

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

function solution(A)

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

Note: All arrays in this task are zero-indexed, unlike the common Lua convention. You can use `#A` to get the length of the array A.

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

int solution(NSMutableArray *A);

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

function solution(A: array of longint; N: longint): longint;

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

function solution($A);

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

sub solution { my (@A)=@_; ... }

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

def solution(A)

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

def solution(a)

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

object Solution { def solution(a: Array[Int]): Int }

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

public func solution(inout A : [Int]) -> Int

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

public func solution(_ A : inout [Int]) -> Int

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

**1, 2, 1, **1], [**1, 2, **1,** 1**], [**1, **2,** 1, 1**], and [1, **2, 1, 1**], but they create only three different sequences: (1, 2, 1), (1, 1, 1) and (2, 1, 1). The correct answer for this example is 3. Notice that the order of performances matters, so the first and the last sequences are considered different.

Write a function:

Private Function solution(A As Integer()) As Integer

^{9} + 7 (1,000,000,007).

For example, given A = [1, 2, 1, 1], the function should return 3 as exmplained above.

Given A = [1, 2], the function should return 0. Kate cannot use all three tickets in only two days.

Assume that:

- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [1..N].

Complexity:

- expected worst-case time complexity is O(N);

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